totally lost c++ help again -__-"

[Locust]

NOTE... I dont want the actual answer of the syntax to solve the problem i want the strategy good damn it i like to figure it out on my own so dont spoil it for me if i cant do it i will ask for the actual answer myself..until then..hint me guys..


after sucessfully completeing the first assignment becuz of the gurus here.. i was doing epic i was doing assignment and lab assignments like a pro..gentlmen i have come to the point where my teacher has stumped me again.. i now need the help..
dont worry i did try this time.. phas gaya hoon..

TASK: take 10 input values from the user and show the maximum and minimum value..
ok here is wat i did...
FIRST THE HIGH NUMBER PART...i will figure the small value after that..

void main()
{
.
BLA BLA BLA YADDA YADDA;
.
for(int i=0;i<=0;i++)
{
cin>>N;
}
.
.
BLAH BLAH BLAH YAADA YADDA YADD
for(int a=0; a<=8; a++)
{
if( N > N[i+1] )
high=N;

BLA BLA BLA

here is my question... assuming the loop goes once cuz of the if statement it will compair N[0] and N[1] then on the next run N[1]>N[2]
wat if N[2] is greater then N[0]????
how do i make it so that all the N[0] to N[9] compair each other.. again no smart pants moves i might not get..

YESH!!! HELP ME NOW..

 

[Crow]

Don't compare N to N[i+1].

Set a new variable (suppose "max"), and set it to the first value of the array, i.e., max = N[0].

Now, inside the loop...

if(max < N)
max = N;

Done.

 

[Locust]

Man why did u do that?? I dont want it to be solved i wanted hints i like figuring out on my own... Khair good thing is i didnt get a word u jus said.. Khair.. Gimme a hint.. Do i need 2 if statements for max and min value or would one do it?

 

[cinderella man]

^ i think u wud need 2 loops....

 

[Locust]

Ahan interesting.. By 2 loops u mean one for input and one for checking and solving the greater and smaller integer values??? I already know that..i m asking bout the if statement that would differentiate the greater and smaller value..like for xample.. Do i need 2 if statements for larger and smaller seperatly..or do i have to use 1 only that would sort both out... If i need 2.. Put goes after ...'else'... In both the statements?

 

[Ottoman]

Would you be more specific Locust? If i'm getting it right the user is inputting ten integer values. The program then displays only the maximum and minimum values? Or is it in the ascending/descending order?

 

[Crow]

Man why did u do that?? I dont want it to be solved i wanted hints i like figuring out on my own... Khair good thing is i didnt get a word u jus said.. Khair.. Gimme a hint.. Do i need 2 if statements for max and min value or would one do it?

You need two statements and two variables (you can do both in one loop).

Suppose a series: 2, 22, 77, 3, 43, 17, 23, 74, 88, 19

For maximum value, you will take a variable and compare it with all the elements in the series. As a starting point, we set the variable ("max") as the first element so we can compare it with the rest of the series.

So here, we suppose max = 2.

Now we compare this with all the elements in the series one by one. When it encounters an element that is greater than "max", we set it equal to "max" (because we are finding the maximum value). So in this series, max will be equal to 22, then 77, and then 88. Thus, when the loop ends, max = 88.

Once you understand this, you can find the minimum value easily, which is done similarly.

 

[ASKnASK]

Basic C++... Gotta love it I'm stuck in my final project (OOP) these days -.- But that's Java, not C++.

Now I haven't read the other posts so maybe its already explained but... here:

You make two variables, suppose iMin, iMax.
Now tell your program that the Array's first value (iNumbers[0]) is minimum, as well as maximum. This is just a place from where your program can start.

Now, inside a for loop that executes 10 times, compare all values of iNumbers array to your iMin. If you come across a number that is less that iMin, update iMin (iMin=iNumbers[blah]).
Same goes for iMax.

If you want the code... you'll have to come up with it yourself

 

[u0sama]

u have two create two loops like this
for(int a=0;a<9;a++)
{
for(b=a+1;b<10;b++)
{
if(n[a]>n)
then swapping

n[0] will be minimum
n[9] will be maximum

 

[eViLrAcEr]

what everyone is effectively saying is just bubble sort the damn thing and get the first and the last values

 

[mubaidr]

+1 for both Usama and Arsal, u can do this in both ways
and offcourse the bubble sort thingy...

 

[Locust]

and the winner this time is.....DRUM ROLL PLEASE!!!!!

ARSAL BHAI!!!!! *dances*

k yo i fugured it out...lab task 2 completed...ZING!!! =D

please stay tuned on saturday i come here with new amazing NOOBISH problems.. thanks to everyone again...

just in case

C++ Guru Score Count:-
Arsal 1
Mubaidr 1

xD

 

[Crow]

Haha, I've only done a C++ basic course in the first semester I can hardly be considered a guru.

But glad I could help.

 

[mubaidr]

(2)

please stay tuned on saturday i come here with new amazing NOOBISH problems..

(lmao)