7As in Olevels isn't hard to get. Trust me on this one. Not hard AT ALL!I dont know really. Past papers. They're pretty easy. I'll do GCSE and IGCSE both. Basically you just need to know how to draw flow charts, draw a web layout, algorithm basics and system development life cycle. The rest is based on your thinking. It never took me more than 20-30 minutes to solve the papers in school.
And how was Chem? I got a some stuff wrong. Not sure about an A* but hoping for I'm pretty confident about an A at least.
This sucks though. I need 7As to get the scholarship in A level. I totally failed urdu first language.I need 5 As in all the other subjects now -.-
The Official ‘O Levels’ Thread
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^Yeah but I have just five subjects left and I need an A in all of them.
Plus I have the worst date sheet. No time to study between commerce/physics/maths exams.
Plus I have the worst date sheet. No time to study between commerce/physics/maths exams.
Worst date sheet?
Go back and look at mine, then tell me who's is worse :hah:
(Add Math 1 + Sociology 2, Add Math 2 + Sociology 1, Physics 1 + Physics 2 + Commerce 1, Physics 4 + Commerce 2, Chemistry 4(Or was it Bio 6
) + EM1). I think it was this. A paper up or down, but it was like this. Consecutive days. AM PM sessions each day. That week literally killed me. I studied for Sociology coming out of the Add Math exam (Hadn't studied it before.). Even slept for 20 mins in Sociology 1 (or 2. Which ever was on the second day) haha.
You're one crazy dude!Worst date sheet?
Go back and look at mine, then tell me who's is worse :hah:
(Add Math 1 + Sociology 2, Add Math 2 + Sociology 1, Physics 1 + Physics 2 + Commerce 1, Physics 4 + Commerce 2, Chemistry 4(Or was it Bio 6
IGCSE Mathematics Formula Booklet ( 2012 Updated).pdf
Math nuublets might find this useful. Niggers, get the one mark I couldn't and get the distinction. Don't leave out anything. The regret is too damn high. Been there, done that.
Abuses will lead to ban up kerna hai to make sure it's more than one mark :hah:
Also remember, Order 1 of symmetry is the same as Order 0.
Math nuublets might find this useful. Niggers, get the one mark I couldn't and get the distinction. Don't leave out anything. The regret is too damn high. Been there, done that.
Abuses will lead to ban up kerna hai to make sure it's more than one mark :hah:
Also remember, Order 1 of symmetry is the same as Order 0.
How does one revise for Physics in a day? I've done 3 theory past papers and a bunch of MCQ ones, a few weeks back. Now I'm going through the book properly. Any tips?
Despite giving lots of theory papers for the past three years, I still can't predict what the paper is going to be like. Is there any particular format they follow? Like in Chemistry, the first question would be to identify elements, the second would be about ionic equations and crap, and the last few would always have one question from Organic Chemistry and one from equilibrium reactions.
[MENTION=25983]AbbY[/MENTION]
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Also, what is linear magnification, and how do you calibrate a thermometer (or any instrument for that matter)?
Despite giving lots of theory papers for the past three years, I still can't predict what the paper is going to be like. Is there any particular format they follow? Like in Chemistry, the first question would be to identify elements, the second would be about ionic equations and crap, and the last few would always have one question from Organic Chemistry and one from equilibrium reactions.
[MENTION=25983]AbbY[/MENTION]
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Also, what is linear magnification, and how do you calibrate a thermometer (or any instrument for that matter)?
Jeez guys! Screw the pattern. Do everything and you'll not have to worry about patterns :/
__
Image Size / Object Size IIRC.
Thermocouple thermometer?
^I'll obviously study everything, but it's good to know how the paper is going to be laid out.
Any thermometer. I saw this question in the past papers, I think it might be about the Lower and Upper fixed points.
Any thermometer. I saw this question in the past papers, I think it might be about the Lower and Upper fixed points.
For alcohol thermometers, you need to take the ice point, the steam point and divide the rest into 100 divisions.
Basically, you take a funnel and fill it with ice and let the water drip into a beaker/drain. Then you immerse the thermometer in the middle of the ice. The steady reading is 0.
Next you take a boiling flask and boil water. This time do not immerse the thermometer in water, water just above it so that steam temp is registered, not water. The flask has to be covered from the top with a bung, the thermometer coming thru the bung and an exhaust tube to let the vapor escape (so that the system doesn't get too pressurized). Steady reading is 100.
Next you simply divide it into even readings.
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Also, do make sure you read up on thermocopules. They're not too important, but I remember a 3-5 mark question on drawing the figure where one junction is the ice point and the other hot water with a mV meter in between and different wires labelled.
... Man I'm totally failing maths... I didnt know the difference between a matrix and a vectors question. And I spent most of my time studying physics
But well the first question is I guess like.
i) 6
ii) 14+44+78+45+18 / 2+4+6+3+1
= 12.43 = 12.4
^ I think this is wrong.
iii) the probability is either 2/16 + 14/15 or 2/16 x 14/15
I still have to study most of the concepts tomorrow.
iv) The formula is height = freq. density x class width
Therefore 4 x 2 = 8. Similarly 5x2 = 10. So the answer is 10cm
I'm not sure about these answers I suck at math I just wanted to do it for practice
And yeah I have no idea how the second one works. Still have to study vectors.
But well the first question is I guess like.
i) 6
ii) 14+44+78+45+18 / 2+4+6+3+1
= 12.43 = 12.4
^ I think this is wrong.
iii) the probability is either 2/16 + 14/15 or 2/16 x 14/15
I still have to study most of the concepts tomorrow.
iv) The formula is height = freq. density x class width
Therefore 4 x 2 = 8. Similarly 5x2 = 10. So the answer is 10cm
I'm not sure about these answers I suck at math I just wanted to do it for practice
And yeah I have no idea how the second one works. Still have to study vectors.
^Most of those are incorrect ._.
I've been weak at math for years, but I decided to improve this year. I did past papers (Topical) for 2 months and then did yearly every once in a while. Plus, I've been doing a yearly past paper every night ever since the CIEs started ._.
And I'm still not A* material.
Point is, you gotta start studying math immediately! It's not something you can take lightly.
[MENTION=25983]AbbY[/MENTION]: Could you take a shot at those questions?
I've been weak at math for years, but I decided to improve this year. I did past papers (Topical) for 2 months and then did yearly every once in a while. Plus, I've been doing a yearly past paper every night ever since the CIEs started ._.
And I'm still not A* material.
Point is, you gotta start studying math immediately! It's not something you can take lightly.
[MENTION=25983]AbbY[/MENTION]: Could you take a shot at those questions?
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@Xerolt9
Here is the answer to your questions. The * symbol denotes multiplication.
For the first question:
1) 2+4+(6/2) = 9
2)
mean = (7.5*2+11*4+13*6+15*3+18*1)/(2+4+6+3+1) = ( 15+44+78+45+18 ) /16 = 12.5
3) (14/16)*(2/16) = 28/256 = 7/64
4) 4 children are represented by length of 8
1 child is represented by length of 8/4 =2
2 children are represented by length of 2*2 = 4 (answer)
For second question:
1) The best idea is to draw a diagram then see how to solve the question. If you draw PQ and PR they would both lie in the fourth quadrant (assuming P at origin). Since R lies on PQ essentially what that means is that both PQ and PR make the same angle with the horizontal.
9/3 = 6/h
h=2
2) PU = PQ + QU = (10 -7) (just writing column as a row because of obvious limitations)
first component of PU = 3+7 = 10
second component of PU = -9 + 2 = -7
3) if U is the mid-point of QS that means:
QU = QS/2
or QS = 2* QU
we already know QU is (7 2). So QS will be (14 4)
now PS = PQ + QS
if you look at the second components of this vector equation you get:
k = -9+4 = -5
If you actually draw the diagram taking P as reference (origin), then the answer becomes clearer to see.
Here is the answer to your questions. The * symbol denotes multiplication.
For the first question:
1) 2+4+(6/2) = 9
2)
mean = (7.5*2+11*4+13*6+15*3+18*1)/(2+4+6+3+1) = ( 15+44+78+45+18 ) /16 = 12.5
3) (14/16)*(2/16) = 28/256 = 7/64
4) 4 children are represented by length of 8
1 child is represented by length of 8/4 =2
2 children are represented by length of 2*2 = 4 (answer)
For second question:
1) The best idea is to draw a diagram then see how to solve the question. If you draw PQ and PR they would both lie in the fourth quadrant (assuming P at origin). Since R lies on PQ essentially what that means is that both PQ and PR make the same angle with the horizontal.
9/3 = 6/h
h=2
2) PU = PQ + QU = (10 -7) (just writing column as a row because of obvious limitations
)first component of PU = 3+7 = 10
second component of PU = -9 + 2 = -7
3) if U is the mid-point of QS that means:
QU = QS/2
or QS = 2* QU
we already know QU is (7 2). So QS will be (14 4)
now PS = PQ + QS
if you look at the second components of this vector equation you get:
k = -9+4 = -5
If you actually draw the diagram taking P as reference (origin), then the answer becomes clearer to see.
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3) Shouldn't it be, (14/16 * 2/15) + (2/16 * 14/15) ?
4) The answer in the marking scheme and solved past papers is 1.6
Yeah, I messed up the answer to (iii). Your answer seems right.
A good way is to draw the tree up till depth 2. Two of the nodes will have probability that add up to the answer you just wrote. The other two nodes will have probability (14*13)/(16*15) and (2*1)/(16*15). All the four terms (that is, your answer and these two terms I wrote) should add to 1 (and they do).
As for (iv), I don't know. Perhaps there is some specific fact that I am not aware of.
A good way is to draw the tree up till depth 2. Two of the nodes will have probability that add up to the answer you just wrote. The other two nodes will have probability (14*13)/(16*15) and (2*1)/(16*15). All the four terms (that is, your answer and these two terms I wrote) should add to 1 (and they do).
As for (iv), I don't know. Perhaps there is some specific fact that I am not aware of.
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It was horrible :\
A really weird number patterns question showed up. Save for a handful, none of the candidates were able to get it right.
Probabilities (which I normally find easy) were given in a very twisted way.
I'm losing 10 marks as it is. I didn't even get time to recheck my paper, so I'm guessing more mistakes will show up.
A really weird number patterns question showed up. Save for a handful, none of the candidates were able to get it right.
Probabilities (which I normally find easy) were given in a very twisted way.
I'm losing 10 marks as it is. I didn't even get time to recheck my paper, so I'm guessing more mistakes will show up.
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