Can Anyone Solve This ?

[puppet]

The riddle is incomplete, stupid and redundant.

It does not pose any solution its own right.

EVERY solution will be messing around with the numbers or adding/deleting something.

TECHNICALLY 15+15 = 30 is correct here because it doesn't say fill all the boxes.

But then again its an argument about what the questions says and says not.

1/10 poorly done riddle. no logical answer.

agree, someone noob made this riddle

 

[HAMMER of THOR]

three odd numbers will always add up to be odd so there is no possible way for you to solve this unless you go like 1.3+15.7+13... which is perfectly legal as it says that only use the following numbers and you are using those numbers only...

 

[KDKHAN]

The riddle is incomplete, stupid and redundant.

It does not pose any solution its own right.

EVERY solution will be messing around with the numbers or adding/deleting something.

TECHNICALLY 15+15 = 30 is correct here because it doesn't say fill all the boxes.

But then again its an argument about what the questions says and says not.

1/10 poorly done riddle. no logical answer.

This question came in UPSC (Union Public Service Commission, India) Final Exams held in Dec 2013.

 

[Newton]

Yes but what it allowed dos not include "point"

in some places the , is used instead of the .

for example

what we write as 9,500.00 they write as 9.500,00 i dont know the reason behind it but using this we can say

7,5+7,5+10

This question came in UPSC (Union Public Service Commission, India) Final Exams held in Dec 2013.

i think that part of it is fake

also there is a rule

ODD + ODD = EVEN
EVEN + EVEN = EVEN
ODD + EVEN = ODD

so technically you can't get an even number by adding 3 odd numbers

 

[YanZZah]

well if Q doesn't simplify or gives us a clear information then will say try manoeuvring ... flipping the given numbers: only one number 9 can bring about 6 if flipped (upside down) rest are just cacography with vague projection.

9 + 6 (flipped 9) + 15 = 30

else there is no way answer can be 30 with odd numbers present.

 

[KDKHAN]

so technically you can't get an even number by adding 3 odd numbers

But factually, examiner does not demand or restrict to only 3 odd number.

 

[Newton]

But factually, examiner does not demand or restrict to only 3 odd number.

which is why you can use

7,5+7,5+15

 

[crazyhassan]

@Kd khan bhai exam me choice pe b chor sktay han,
Next question please

 

[Cerberus]

I run all the logic in program
answer is not 30
so not possible

 

[DivineTerra]

This question came in UPSC (Union Public Service Commission, India) Final Exams held in Dec 2013.

 

[Mooziefy]

15+0+15..

 

[YanZZah]

^using the numbers provided and there is no '0' number given. lol

 

[sTraNg3r]

People are running in circles here.

 

[DivineTerra]

Clearly there is only one right solution that actually makes sense without ultimately mending the original question and the rules and that is to use decimals.....

 

[The Suspect]

Got it!
15 + 13 + (3-1) = 30

 

[Benighted]

No I can't solve this.

 

[EternalBlizzard]

Well i googles this shit and found this answer:
"Use an odd base from 11 up to 19. Then you can pick two even numbers (written out as 11, 13, or 15) and one of the odd numbers (1, 3, 5, 7 ,9). If they add up correctly you have provided a correct solution. Here are all the ones I was able to find, with addends from largest to smallest, ignoring other permutations."

​
could someone explain this please?
source

He changed the bases of the numbers... since it wasn't specified if it was necessary to put it in decimal

15(base11) + 15(base11) + 1(base11) = 30(base11)

How..?

Decimal -
0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16...
Base 11 -
0,1,2,3,4,5,6,7,8,9,A,10,11,12,13,14,15......

Now Adding them...
15(9)
15(9)
+1(9)
---
30(9)
Adding least significant bits... ( 5 + 5 + 1 = 11 )
11 in base 11 is "10"
We write 0 and carry "1" then ( 1+1+1 = 3)
Dats how we get 30( in base 11)

If im correct.... we can get it by using base 9 too...

15(9)
13(9)
+1(9)
---
30(9)
Since 5 + 3 + 1 = 9 and 9 in base 9 is "10"

The trick is to choose a base in which an odd number has the representation that has "0" in the end and this only happens in odd bases i guess... In octal "10" equals 8 so it won't work cuz we cant get 8 ( all odd).

 

[puppet]

He changed the bases of the numbers... since it wasn't specified if it was necessary to put it in decimal

15(base11) + 15(base11) + 1(base11) = 30(base11)

How..?

Decimal -
0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16...
Base 11 -
0,1,2,3,4,5,6,7,8,9,A,10,11,12,13,14,15......

Main part is Adding...
15
15
+1
---
30
Adding least significant bits... ( 5 + 5 + 1 = 11 )
11 in base 11 is "10"
We write 0 and carry "1" then ( 1+1+1 = 3)
Dats how we get 30( in base 11)

lol

but c'mon guys its not a problem that must be solved jo software engineer bane hovay ho sab k kiasay b isko solve karna hi krna he :crazy:

agr bht shok he algorithms banae ka then lets create a thread for creating algos of complex problem

 

[KDKHAN]

@Kd khan bhai exam me choice pe b chor sktay han,
Next question please

No choice here. When decision goes to 3rd empire, its out or not out.

I am giving you guys here a very big hint which might help you.

"you can also repeat the numbers so repeat the numbers you choose"

Concentrate on this hint and try again.

 

[Sady96]

Sum to 2 odds is even so convert them to even and add (5+7)+(9+3)+(1+5)=30.